Discussion
The digits of a two-digit number add up to 12, and the number formed by reversing them is 18 greater. The number is:
Answer: A
Let the number be \( 10a + b \) with \( a + b = 12 \).
Reversing adds 18:
\[ (10b + a) - (10a + b) = 9(b - a) = 18 \quad\Longrightarrow\quad b - a = 2 \]
\[ a = 5, \quad b = 7 \quad\Longrightarrow\quad 57 \]
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