Discussion
The digits of a two-digit number have product 18 and sum 9. The larger of the two numbers that satisfy this is:
Answer: B
Two digits with sum 9 and product 18 are 3 and 6, since \(3 + 6 = 9\) and \(3 \times 6 = 18\). They can be arranged as 36 or 63, and the larger is 63. Treating the digits as roots of \(x^2 - 9x + 18 = 0\) finds them directly.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development