Discussion
A positive number decreased by 8 equals 128 times its reciprocal. The number is:
Answer: D
The condition is \(x - 8 = \dfrac{128}{x}\). Multiplying by \(x\) gives \(x^2 - 8x - 128 = 0\), which factors as \((x - 16)(x + 8) = 0\). The negative root is rejected because the number is positive, leaving \(x = 16\). Check: \(16 - 8 = 8\) and \(128 \div 16 = 8\).
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development