Discussion
The product of two consecutive positive integers is 156. The smaller integer is:
Answer: A
Solve \(n(n+1) = 156\), so \(n^2 + n - 156 = 0\) and \((n + 13)(n - 12) = 0\), giving \(n = 12\). The integers are 12 and 13. A quicker route is to note that \(\sqrt{156} \approx 12.5\), so the pair must straddle that value.
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