Discussion
Two positive integers have a product of 156. If one of them is one more than the other, the larger integer is:
Answer: C
Consecutive integers multiplying to 156 satisfy \(n(n+1) = 156\), so \(n^2 + n - 156 = 0\) and \((n + 13)(n - 12) = 0\), giving \(n = 12\). The pair is 12 and 13, so the larger is 13. Since \(\sqrt{156} \approx 12.5\), the two integers must straddle that value, which locates them at once.
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