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The difference between the squares of two consecutive natural numbers is 35. The larger number is:

  • A.18
  • B.16
  • C.17
  • D.19

Answer: A

For consecutive numbers, \((n+1)^2 - n^2 = 2n + 1\). Setting \(2n + 1 = 35\) gives \(n = 17\), so the larger number is 18. Check: \(18^2 - 17^2 = 324 - 289 = 35\). The difference of consecutive squares is always odd, and equals the sum of the two numbers.

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