Discussion
The sum of the squares of two consecutive even integers is 340. The smaller integer is:
Answer: B
Let the integers be \(n\) and \(n + 2\). Then \(n^2 + (n+2)^2 = 340\), so \(2n^2 + 4n - 336 = 0\) and \(n^2 + 2n - 168 = 0\), which factors as \((n + 14)(n - 12) = 0\). Taking the positive root, \(n = 12\). Check: \(144 + 196 = 340\).
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