Discussion
The square of a number exceeds the number itself by 132. The positive value of the number is:
Answer: C
The condition is \(x^2 - x = 132\), so \(x^2 - x - 132 = 0\) and \((x - 12)(x + 11) = 0\). The positive root is 12. Check: \(144 - 12 = 132\). Looking for two factors of 132 that differ by 1 finds 11 and 12 immediately.
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