Discussion
The least number that must be added to 1056 to make it exactly divisible by 23 is:
Answer: C
Dividing 1056 by 23 gives 45 with a remainder of 21, since \(23 \times 45 = 1035\). To reach the next multiple, \(23 \times 46 = 1058\), we must add \(1058 - 1056 = 2\). The remainder 21 is what must be added to reach the multiple only if we were subtracting instead.
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