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A number leaves remainder 4 when divided by 7. The remainder when twice that number is divided by 7 is:

  • A.1
  • B.2
  • C.4
  • D.6

Answer: A

Write the number as \(7k + 4\). Twice it is \(14k + 8 = 7(2k + 1) + 1\), so the remainder is 1. Working with remainders directly, \(2 \times 4 = 8\) and \(8\) leaves 1 on division by 7 - remainders can be multiplied and then reduced.

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