Discussion
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is
Answer: D
The third integer is 15.
Three consecutive odd integers can be written \(x\), \(x + 2\), \(x + 4\). The condition is
\[ \begin{aligned} 3x &= 2(x + 4) + 3 \\ 3x &= 2x + 11, \quad x = 11 \end{aligned} \]
So the integers are 11, 13 and 15, and the third is 15. Check: \(3 \times 11 = 33\) and \(2 \times 15 + 3 = 33\). 11 is the first integer, a common slip, and 13 is the middle one.
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