Discussion
In his will, Rushveer Singh distributed all his money among his 3 children. The eldest one got Rupees 2 lakh more than 50% of the total money, while the younger one got Rupees 3 lakh less than 25% of the total money. The remaining money went to the middle child, who bought a house with 50% of the money he got, and was left with Rupees 6 lakh less than what the youngest one got. How much money did the youngest one get ?
Answer: C
The youngest child got ₹ 16 lakh.
Let the total be T lakh. The eldest got 0.5T + 2 and the youngest 0.25T - 3, so the middle child got the rest:
\[ \begin{aligned} M &= T - (0.5T + 2) - (0.25T - 3) \\ &= 0.25T + 1 \end{aligned} \]
After spending half on a house, he had 6 lakh less than the youngest:
\[ \begin{aligned} 0.125T + 0.5 &= (0.25T - 3) - 6 \\ 0.125T &= 9.5 \Rightarrow T = 76 \end{aligned} \]
The youngest got 0.25 × 76 - 3 = 16 lakh. Check: the eldest got 40 lakh and the middle child 20 lakh, keeping 10 lakh after buying the house, which is 6 lakh less than 16.
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