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A train running at the speed of 72 km/ hr passed a man in 14 sec and a platform in 32 sec respectively. Find the length of the platform.

  • A.360 meter
  • B.280 meter
  • C.210 meter
  • D.240 meter

Answer: A

The platform is 360 meter long.

Convert the speed: \(72 \times \frac{5}{18} = 20\) m/s. Passing a man, the train covers its own length; passing a platform, its length plus the platform's.

\[ \begin{aligned} \text{train} &= 20 \times 14 = 280\ \text{m} \\ \text{train + platform} &= 20 \times 32 = 640\ \text{m} \\ \text{platform} &= 640 - 280 = 360\ \text{m} \end{aligned} \]

280 m is the train's own length, the usual trap.

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