Discussion
There are 2 trains P and Q moving in same direction. They are of equal length and cross a stationary pole in 5 seconds and 6 seconds respectively. In how much time would they cross each other?
Answer: C
Let each train be \( L \) metres long. Crossing a pole gives each speed:
\[ v_{P} = \frac{L}{5}, \qquad v_{Q} = \frac{L}{6} \]
Moving the same way, they close at the difference:
\[ v_{P} - v_{Q} = \frac{L}{5} - \frac{L}{6} = \frac{L}{30} \]
To cross, the faster must cover both lengths, \( 2L \):
\[ t = \frac{2L}{L/30} = 60 \text{ seconds} \]
The length cancels, so it never needs a value.
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