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A train travels between P and Q in 3 hours. When the speed of train is increased by 6 km/hr, then it covers the same distance in 2 hours. What is original speed of train? Also find the distance between P and Q?

  • A.Distance = 48 km; Speed = 16 km/hr
  • B.Distance = 36 km; Speed = 12 km/hr
  • C.Distance = 51 km; Speed = 17 km/hr
  • D.Distance = 54 km; Speed = 18 km/hr

Answer: B

The distance is the same both ways, so equate the two expressions for it.

\[ 3v = 2(v + 6) \]

\[ 3v = 2v + 12 \quad\Longrightarrow\quad v = 12 \text{ km/hr} \]

\[ D = 3 \times 12 = 36 \text{ km} \]

Checking: at 18 km/hr the same 36 km takes 2 hours.

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