Discussion
Stations A and B are 220 km apart. A train leaves towards station B with speed of 40 km/hr at 10 pm. Another train leaves towards station A from station B with speed of 50 km/hr at 11 pm. At what time both trains meet?
Answer: C
The first train has a one-hour head start.
\[ \text{covered by 11 pm} = 40 \times 1 = 40 \text{ km} \]
\[ \text{gap remaining} = 220 - 40 = 180 \text{ km} \]
From 11 pm they approach at \( 40 + 50 = 90 \) km/hr:
\[ t = \frac{180}{90} = 2 \text{ hours} \]
So they meet at 1 am. Ignoring the head start would give a meeting at about 12:27 am.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development