Discussion
A train travels a certain distance by taking 3 stops of 20 minutes each. Considering the period of stoppage, the overall speed of the train comes to 40 kmph; while without consideration of stoppage, it is 60 kmph. How much distance must the train have travelled ?
Answer: B
Three stops of 20 minutes cost exactly one hour, so the journey with stops takes an hour longer.
\[ \frac{D}{40} - \frac{D}{60} = 1 \]
\[ D\left(\frac{3 - 2}{120}\right) = 1 \quad\Longrightarrow\quad D = 120 \text{ km} \]
Checking: 3 hours with stops against 2 hours of pure running.
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