Discussion
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: B
The man runs the same way, so the train closes on him at the difference of the speeds and covers only its own length.
\[ \text{relative speed} = \frac{125}{10} = 12.5 \text{ m/s} = 12.5 \times \frac{18}{5} = 45 \text{ km/hr} \]
\[ v_{\text{train}} = 45 + 5 = 50 \text{ km/hr} \]
The man's speed is added back because it had been subtracted to give the relative speed.
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