Discussion
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: C
Trains moving in the same direction close at the difference of their speeds; in opposite directions, at the sum.
\[ \text{relative speed} = 60 + 90 = 150 \text{ km/hr} = 150 \times \frac{5}{18} = \frac{125}{3} \text{ m/s} \]
\[ \text{total length} = 1100 + 900 = 2000 \text{ m} \]
\[ t = \frac{2000 \times 3}{125} = 48 \text{ seconds} \]
The lengths are given in kilometres and must be converted to metres first.
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