Discussion
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: C
The jogger runs the same way, so the train closes at the difference of the speeds.
\[ \text{relative speed} = 45 - 9 = 36 \text{ kmph} = 36 \times \frac{5}{18} = 10 \text{ m/s} \]
To pass him completely, the train must cover the 240 m gap plus its own 120 m:
\[ t = \frac{240 + 120}{10} = 36 \text{ seconds} \]
Covering only the 240 m gap brings the engine level with the jogger, not the whole train past him.
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