Discussion
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer: D
Trains moving in the same direction close at the difference of their speeds; in opposite directions, at the sum.
\[ \text{relative speed} = \frac{108 + 112}{6} = \frac{220}{6} = 36.67 \text{ m/s} \]
\[ 36.67 \times \frac{18}{5} = 132 \text{ km/hr} \]
\[ v_{2} = 132 - 50 = 82 \text{ km/hr} \]
The relative speed is the sum here, so the known 50 km/hr is subtracted from it to leave the second train's speed.
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