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The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is:

  • A.850
  • B.525
  • C.550
  • D.750

Answer: D

\[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \]

\[ 90 \text{ km/hr} = 25 \text{ m/s} \]

In one minute the train covers

\[ 25 \times 60 = 1500 \text{ m} \]

That is the train plus the platform, and the two are equal:

\[ 2L = 1500 \quad\Longrightarrow\quad L = 750 \text{ metres} \]

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