Discussion
A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
Answer: B
A pole has no length, so the first crossing gives the speed.
\[ v = \frac{240}{24} = 10 \text{ m/s} \]
\[ t = \frac{240 + 650}{10} = \frac{890}{10} = 89 \text{ seconds} \]
Using only the platform's 650 m would give 65 seconds - the first distractor.
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