Discussion
A person bought some oranges at the rate of 3 oranges per rupee. He bought the same number of oranges at the rate of 2 oranges per rupee. He mixes both the types and sells at 5 for rupees 2. In this business he bears a loss of Rs. 3. How many oranges did he buy in total?
Answer: C
Suppose he bought n oranges of each kind. At 3 oranges per rupee the first lot cost n/3 rupees, and at 2 oranges per rupee the second lot cost n/2 rupees, so the total cost is 5n/6. He had 2n oranges, sold at 5 for Rs. 2, which brings 2n x 2/5 = 4n/5. The loss is 5n/6 - 4n/5 = n/30, and this equals Rs. 3, so n = 90. He bought 90 + 90 = 180 oranges, option (C). The value 90 is the number of each kind, and 150 and 300 do not give a loss of Rs. 3.
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