Discussion
A dishonest dealer professes to sell his goods at cost price, but he uses a weight of 970 grams for a kg weight. Find his gain percentage.
Answer: C
His gain is 3 9/97 %.
He sells 970 g as 1000 g, so the goods that cost him for 970 g are sold for the price of 1000 g. The gain is the 30 g difference on the 970 g.
\[ \frac{30}{970}\times100=\frac{300}{97}=3\frac{9}{97}\% \]
The other options are not equal to 300/97.
This is a common result: when a dealer uses a false weight, the gain percentage is (error / true weight used) × 100. Here the error is 30 g and the weight actually given is 970 g, which gives 3 9/97%. Using 1000 g as the base would give 3%, which is not an option.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development