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A man buys a field of agricultural land. He sells one-third of the land at a loss of 20% and two-fifth of the land at a profit of 25%. At how much percent profit must he sell the remaining land so as to make an overall profit of 10% ?

  • A.25%
  • B.20%
  • C.18%
  • D.15%

Answer: A

He must sell the remaining land at 25% profit.

Let the whole field cost 1 (one unit). One-third and two-fifths are sold, so the rest is \(1 - \frac{1}{3} - \frac{2}{5} = \frac{4}{15}\). For a 10% overall profit, total sales must be 1.1:

\[ \begin{aligned} \tfrac{1}{3}(0.8) + \tfrac{2}{5}(1.25) &= \tfrac{4}{15} + \tfrac{1}{2} \\ &= \tfrac{23}{30} \\ \text{rest} &= 1.1 - \tfrac{23}{30} = \tfrac{1}{3} \\ \tfrac{1}{3} \div \tfrac{4}{15} &= 1.25 \end{aligned} \]

So the remaining land must fetch 1.25 times its cost, a profit of 25%. The lower options would leave the overall profit below 10%.

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