Discussion
Find the sum of all integers between 100 and 1000 that are divisible by 9.
Answer: A
The numbers are 108, 117, ..., 999. This is an A.P. with \(a=108, d=9, a_n=999\). Number of terms: \(999=108+(n-1)9 \Rightarrow 891=(n-1)9 \Rightarrow n-1=99 \Rightarrow n=100\). Sum = \(\frac{100}{2}(108+999) = 50(1107) = 55350\).
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development