Discussion
Find the sum of the series: \(1^2 + 2^2 + 3^2 + ... + 10^2\).
Answer: B
The sum of the squares of the first n natural numbers is given by the formula \(S_n = \frac{n(n+1)(2n+1)}{6}\). Here, n=10. \(S_{10} = \frac{10(10+1)(2 \times 10+1)}{6} = \frac{10 \times 11 \times 21}{6} = 5 \times 11 \times 7 = 385\).
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