Discussion
A plane figure whose projected area is half its true area is inclined to the plane of projection at
Answer: B
Correct answer: 60 degrees
The projected area is the true area times the cosine of the inclination, so \[ \cos\theta = 0.5, \qquad \theta = 60^\circ. \] The distractor of 30 degrees comes from taking the sine instead; at 30 degrees the figure would project at 0.866 of its area, not half.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development