Discussion
A line whose plan measures 60 mm and whose ends differ in height by 45 mm has a true length of
Answer: B
Correct answer: 75 mm
The plan length and the height difference are perpendicular, so the true length is the hypotenuse: \[ \sqrt{60^2 + 45^2} = \sqrt{3600 + 2025} = \sqrt{5625} = 75\ \mathrm{mm}. \] The 3-4-5 triangle appears again, scaled by fifteen, which is worth recognising since it saves the arithmetic.
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