Discussion
For that same hexagon the across-flats distance is about
Answer: B
Correct answer: 43.3 mm
The distance across flats is \( \sqrt{3} \) times the side: \[ \sqrt{3} \times 25 = 1.732 \times 25 = 43.3\ \mathrm{mm}. \] It is the shorter of the two hexagon dimensions, standing to the across-corners distance in the ratio \( \sqrt{3} : 2 \), and it is the one that matters when the prism must pass through an opening or be gripped by a spanner.
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