Discussion
The specific heat of a grain is estimated as \( c = 1.0 + 3.2M \) kJ/kg K with \( M \) the dry basis moisture as a fraction. At \( M = 0.18 \) the specific heat is
Answer: A
Correct answer: 1.58 kJ/kg K
Substitute the moisture fraction directly into the correlation:
\[ c = 1.0 + 3.2M = 1.0 + 3.2 \times 0.18 \]
\[ c = 1.0 + 0.576 = 1.576 \approx 1.58\ \mathrm{kJ/kg\,K} \]
Check that \( M \) is used as a fraction, not as 18: entering the percentage would give an absurd 58.6 kJ/kg K. The value sits sensibly between dry grain solids near 1.0 and pure water at 4.18, which is the reassurance that the substitution was made correctly.
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