Discussion
A sample loses \( 12 \) g on oven drying from an initial mass of \( 60 \) g. The dry basis moisture content is
Answer: D
Correct answer: 25.0 per cent
The 12 g lost on oven drying is the water. The dry matter is what remains:
\[ 60 - 12 = 48\ \mathrm{g} \]
On the dry basis:
\[ M_{db} = \frac{12}{48} \times 100 = 25.0\% \]
The distractor 20.0 per cent is the wet basis value, \( 12/60 \), obtained by dividing by the original mass instead of the dry matter. Whenever both figures appear among the options, check which denominator the question asks for - that is usually the whole of the difficulty.
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