Discussion
Comparing a twin and a four-engine aircraft of the same total thrust \( 4T \), with the twin's engines at \( 8 \) m and the four-engine outboard at \( 12 \) m, the ratio of engine-out moments is
Answer: A
Correct answer: 1.33
Keep the total thrust the same. The twin has two engines of \( 2T \) each at 8 m, so losing one leaves a moment of \( 2T \times 8 = 16T \). The four-engine aircraft has engines of \( T \) each, and losing the outboard gives \( T \times 12 = 12T \).
\[ \frac{16T}{12T} = 1.33 \]
So the twin suffers the larger moment despite its shorter arm, because each of its engines carries twice the thrust. Losing one of two is a far greater proportional loss than losing one of four.
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