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A thrust reverser recovers \( 45 \) per cent of an engine's \( 120 \) kN as retarding force. For two engines the total reverse thrust is

  • A.216 kN
  • B.240 kN
  • C.108 kN
  • D.54 kN

Answer: C

Correct answer: 108 kN

Take the recovered fraction per engine, then double it:

\[ 120 \times 0.45 = 54\ \mathrm{kN}, \qquad 54 \times 2 = 108\ \mathrm{kN} \]

Forty-five per cent is typical, because a reverser turns the fan flow through rather less than 180 degrees and does nothing with the core stream on most installations. Note that this force is not credited in the certified landing distance, which assumes brakes alone - the reversers are a margin, not a requirement.

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