Discussion
An inlet must pass \( 180 \) kg/s at a density of \( 0.60 \) kg/m\(^3\) and a velocity of \( 150 \) m/s. The capture area required is
Answer: A
Correct answer: 2.00 m\(^2\)
From the continuity relation \( \dot{m} = \rho A V \):
\[ A = \frac{\dot{m}}{\rho V} = \frac{180}{0.60 \times 150} = \frac{180}{90} = 2.00\ \mathrm{m}^2 \]
The capture area must suit the whole flight envelope, and the mass flow the engine demands varies enormously between takeoff and cruise. An inlet sized for one condition spills air at another, and that spillage carries a drag penalty - which is one of the compromises inlet designers are paid to manage.
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