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An engine of \( 60 \ \mathrm{kg/s} \) air flow produces \( 18 \ \mathrm{kN} \) of thrust. Its specific thrust is

  • A.108 N per kg/s
  • B.300 N per kg/s
  • C.0.33 N per kg/s
  • D.1080 N per kg/s

Answer: B

Dividing gives \( 18\,000/60 = 300 \) newtons per kilogram per second. A high bypass turbofan sits far below this figure and needs a much larger engine for the same total thrust, which is exactly why nacelle diameters grew as bypass ratios rose.

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