Discussion
A \( 1 \ \mathrm{kHz} \) sinusoid of \( 1 \ \mathrm{V} \) peak is applied to that modulator. Slope overload
Answer: A
The sinusoid's steepest slope is at the zero crossing:
\[ \begin{aligned} \text{slope} &= 2\pi f A \\ &= 2\pi(1000)(1) = 6283 \ \mathrm{V/s} \end{aligned} \]
which far exceeds 1280, so overload does occur. The first option computes the slope correctly and then draws the wrong conclusion, which is the trap here. The comparison is always peak input slope against step times clock rate, and either can be adjusted to satisfy it.
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