Discussion
A signal is sampled at \( 20 \ \mathrm{kHz} \). Components at \( 12 \ \mathrm{kHz} \) will appear at
Answer: D
Folding about half the sampling rate:
\[ \begin{aligned} f_{\text{alias}} &= f_{s} - f \\ &= 20 - 12 = 8 \ \mathrm{kHz} \end{aligned} \]
so the component appears at 8 kHz, inside the band and indistinguishable from a genuine signal there. Twelve kilohertz assumes no folding at all, and the remaining options are the sampling rate and the sum. Every component above half the rate has an image below it, which is precisely why the filter must remove them before sampling.
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