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Match List I with List II and select the correct answer using the codes given below :

List IList II
(a) TDM(i) Frequency detector
(b) FM(ii) Envelope detector
(c) AM(iii) Sensitive to propagation delay
(d) FDM(iv) Non-sensitive to propagation delay

  • A.(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
  • B.(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
  • C.(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
  • D.(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)

Answer: A

The correct code is (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv).

TDM interleaves the channels in time slots, so the receiver must stay synchronised with the transmitter and the system is sensitive to propagation delay (iii). FM is demodulated by a frequency detector or discriminator (i). AM is demodulated by an envelope detector (ii). FDM separates channels by frequency, so all of them travel simultaneously and a delay in the path does not mix them up (iv).

The other codes swap the detectors between AM and FM, or assign delay sensitivity to the frequency-division system.

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