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In the 4 \(\times\) 4 array shown below, each cell of the first three rows has either a cross (X) or a number.

1X43
X554
3X6X
    

The number in a cell represents the count of the immediate neighboring cells (left, right, top, bottom, diagonals) NOT having a cross (X). Given that the last row has no crosses (X), the sum of the four numbers to be filled in the last row is

  • A.11
  • B.10
  • C.12
  • D.9

Answer: A

The sum is 11.

Each new number counts the neighbouring cells without a cross. The last row has no crosses, and the row above it reads 3, X, 6, X.

  • Cell 1: neighbours 3 (no cross), X, and cell 2 of the last row: 2.
  • Cell 2: 3, X, 6 above, cells 1 and 3 beside: 4.
  • Cell 3: X, 6, X above, cells 2 and 4 beside: 3.
  • Cell 4: 6 and X above, cell 3 beside: 2.

\[ 2 + 4 + 3 + 2 = 11 \]

The other totals come from counting a cross as clear or forgetting the diagonal neighbours.

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