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In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by :

  • A.5.4 m
  • B.4.5 m
  • C.5 m
  • D.6 m

Answer: D

In these problems the two runners are compared by the distances they cover in the same time, so their speeds are in the ratio of those distances.

\[ A\,100 : B\,90, \qquad A\,100 : C\,87 \]

Both are measured against the same A distance, so

\[ B : C = 90 : 87 \]

In a 180 m race, when B finishes:

\[ C = 180 \times \frac{87}{90} = 174 \text{ m} \]

\[ \text{B beats C by } 180 - 174 = 6 \text{ m} \]

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