Discussion

A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:

Answer: B

Find A's time first.

\[ 5 \text{ km/hr} = 5 \times \frac{5}{18} = \frac{25}{18} \text{ m/s} \]

\[ t_{A} = \frac{100}{25/18} = 72 \text{ s} \]

B gets an 8 m start, so B runs 92 m, and finishes 8 seconds after A:

\[ t_{B} = 72 + 8 = 80 \text{ s} \]

\[ v_{B} = \frac{92}{80} = 1.15 \text{ m/s} = 1.15 \times \frac{18}{5} = 4.14 \text{ km/hr} \]

The start reduces B's distance to 92 m; the 8 seconds are added to A's time.

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