Discussion
In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Answer: A
A finishes in 36 seconds. In that time B, who needs 45 seconds for the full 100 m, covers
\[ 100 \times \frac{36}{45} = 80 \text{ m} \]
\[ \text{A beats B by } 100 - 80 = 20 \text{ m} \]
The 9-second difference is B's time for the remaining 20 m, at \( \tfrac{100}{45} = 2.22 \) m/s.
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