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P can run 100m in 20 second and Q in 25 seconds. P beats Q by

  • A.10 m
  • B.20 m
  • C.25 m
  • D.12 m

Answer: B

P finishes in 20 seconds. In that time Q, who needs 25 seconds for 100 m, covers

\[ 100 \times \frac{20}{25} = 80 \text{ m} \]

\[ \text{P beats Q by } 100 - 80 = 20 \text{ m} \]

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