Discussion
A runs 1.5 Times as fast as B can. If A gives B a start of 50 m, how far must the winning post be in order that A and B reach at the same time
Answer: A
Let the winning post be \( d \) metres away. A runs \( d \), B runs \( d - 50 \), and they finish together.
\[ \frac{d}{1.5} = \frac{d - 50}{1} \]
\[ 2d = 3d - 150 \quad\Longrightarrow\quad d = 150 \text{ m} \]
Checking: A covers 150 m while B covers 100, and \( \tfrac{150}{100} = 1.5 \).
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