Discussion
For an absolutely white or specular body :
Where, Absorptivity = α, Reflectivity = ρ, Transmissivity = τ
Answer: C
For an absolutely white or specular body, ρ = 1 and α = τ = 0.
Incident radiation is absorbed, reflected or transmitted, so \(\alpha + \rho + \tau = 1\). An absolutely white body reflects all the radiation falling on it, diffusely, and a specular body reflects it all like a mirror. In both, the reflectivity is 1, so nothing is absorbed or transmitted.
α = 1 with nothing reflected or transmitted describes a black body. τ = 1 describes a perfectly transparent (diathermanous) body. α + ρ = 1 with τ = 0 is true of any opaque body, so it is not specific to a white body.
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