Discussion
Relative intensities of successive lines in the observed Raman spectra of nitrogen molecule is :
Answer: B
Successive lines alternate in intensity in the ratio 1 : 2.
The \({}^{14}N\) nucleus has spin I = 1, so \({}^{14}N_{2}\) is a homonuclear molecule of bosons. The nuclear spin states split into symmetric and antisymmetric sets with statistical weights in the ratio
\[ \frac{I + 1}{I} = \frac{2}{1} \]
and these combine with even and odd rotational levels respectively. Rotational Raman lines from even-J levels are therefore twice as intense as those from odd-J levels, and successive lines alternate weak and strong in the ratio 1 : 2.
The ratio 1 : 3 is the hydrogen case (I = 1/2, ortho to para 3 : 1). The ratios 3 : 4 and 2 : 3 do not correspond to I = 1.
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