Discussion
At Mach 8 the stagnation temperature of air at 220 K is
Answer: D
The factor is \( 1 + 0.2 \times 64 = 13.8 \), giving \( 220 \times 13.8 = 3036 \) kelvin. No material survives that, and the combustion products would dissociate, which places full deceleration entirely out of the question.
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