Discussion
In a bag, there are coins of \(25 p, 10 p\) and \(5 p\) in the ratio of \(1 : 2 : 3.\) If there is \(Rs. 30\) in all, how many \(5 p\) coins are there?
Answer: C
Let the number of \(25 p, 10 p\) and \(5 p\) coins be \(x, 2x, 3x \) respectively.
Then, sum of there value \(= Rs. (\frac{25x}{100} + \frac{10 \times 2x}{100} + \frac{5 \times 3x}{100}) = Rs. \frac{60x}{100}\)
\(\therefore \frac{60x}{100} = 30 \Leftrightarrow x = \frac{300 \times 100}{60} = 50.\)
Heance, the number of \(5 p\) coins \(= (3 \times 50) = 150.\)
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development